Use setTimeout() inbuilt function to run function after a delay in JavaScript. It’s plain JavaScript, this will call your_func once, after fixed seconds (time).
setTimeout(function() { your_func(); }, 5000);5000 = 5 sec
If a function has no parameters and no explicit receiver you can call directly setTimeout(func, 5000)
JavaScript run function after a delay Example code
HTML example code: Function will call after 1 minute.
<!DOCTYPE html>
<html>
<body>
<button onclick="timeFunction()">Click Here</button>
<script>
function timeFunction() {
setTimeout(function(){ alert(" 1 seconds! Alert"); }, 1000);
}
</script>
<p>Wait for 1 seconds after click...</p>
</body>
</html>Output:
How do I delay a function call for 5 seconds?
A setTimeout is a native JavaScript function, which calls a function or executes a code snippet after a specified delay (in milliseconds).
A setTimeout accepts a reference to a function as the first argument. Alert messages will pop up after 5 seconds automatically.
<!DOCTYPE html>
<html>
<body>
<script>
function greet(){
alert('Hello wrold!');
}
setTimeout(greet, 2000);
</script>
</body>
</html>Output:
How to delay a JavaScript function call using JavaScript?
Answer: To delay a function call, use setTimeout() function. function-name − The function name for the function to be executed.
This might be useful to display a popup after a visitor has been browsing your page for a certain amount of time.
setTimeout(function() { functionName() },5000)Do comment if you have any doubts and suggestions on this JS function-based question and examples program.
Note: The All JS Examples codes are tested on the Firefox browser and the Chrome browser.
OS: Windows 10
Code: HTML 5 Version