Python Print Traceback

Using the print_exc() method or print_exception() method you can Print Traceback in Python. The module defines the following functions:

• traceback.print_exc(limit=None, file=None, chain=True)
• traceback.print_exception(etype, value, tb, limit=None, file=None, chain=True)

Read more: https://docs.python.org/3/library/traceback.html

Python Print Traceback

Simple example code printing the stack trace to handle the exception generated.

Using print_exc() method.

import traceback

A = [1, 2, 3, 4]
try:
    value = A[5]

except:
    # printing stack trace
    traceback.print_exc()

Output:

Using print_exception() method

import traceback
import sys

a = 1
b = 0

try:
    value = a / b

except:
    # printing stack trace
    traceback.print_exception(*sys.exc_info())

Output:

Traceback (most recent call last):
  File "C:\Users\Rohit\PycharmProjects\pythonProject\modules\main.py", line 8, in <module>
    value = a / b
ZeroDivisionError: division by zero

How to catch and print the full exception traceback without halting/exiting the program?

Answer: traceback.format_exc() or sys.exc_info() will yield more info

import traceback
import sys

try:
    x = 1/0
except Exception:
    print(traceback.format_exc())
    # or
    print(sys.exc_info()[2])

Do comment if you have any doubts or suggestions on this Python Traceback topic.

Note: IDE: PyCharm 2021.3.3 (Community Edition)

Windows 10

Python 3.10.1

All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.