Use re.sub() method of the re module to replace the string that matches the RegEx (regular expression) in Python.
A Regular Expression (RE) is a special text string used for describing a search pattern.
re.sub(pattern, repl, string, count=0, flags=0)Python regex find and replace Example
Simple example code.
You have to import the re module, and then we can use its sub() method.
Find all small letter before @ and replace with “ONE”.
import re
str1 = '[email protected]'
print(re.sub('[a-z]*@', 'ONE@', str1))
Output:
Regular expression or RegEx in Python is denoted as RE (REs, regexes, or regex pattern) are imported through re module.
| Identifiers | Modifiers | White space characters | Escape required |
|---|---|---|---|
| \d= any number (a digit) | \d represents a digit.Ex: \d{1,5} it will declare digit between 1,5 like 424,444,545 etc. | \n = new line | . + * ? [] $ ^ () {} | \ |
| \D= anything but a number (a non-digit) | + = matches 1 or more | \s= space | |
| \s = space (tab,space,newline etc.) | ? = matches 0 or 1 | \t =tab | |
| \S= anything but a space | * = 0 or more | \e = escape | |
| \w = letters ( Match alphanumeric character, including “_”) | $ match end of a string | \r = carriage return | |
| \W =anything but letters ( Matches a non-alphanumeric character excluding “_”) | ^ match start of a string | \f= form feed | |
| . = anything but letters (periods) | | matches either or x/y | —————– | |
| \b = any character except for new line | [] = range or “variance” | —————- | |
| \. | {x} = this amount of preceding code | —————– |
Do comment if you have any doubts and suggestions on this Python RegEx example code.
Note: IDE: PyCharm 2021.3.3 (Community Edition)
Windows 10
Python 3.10.1
All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.