Python not in operator evaluates to true if it does not find a variable in the specified sequence and false otherwise. It works exactly the opposite way as the in operator works.
Python not in operator
A simple example code checks the presence of a specified value inside a given sequence (list, string, tuple) but its return values are opposite to that of the in operator.
list1 = [1, 2, 3, 4, 5]
print(5 not in list1) # False
s = "A is A"
print("is" not in s) # False
tuple1 = (11, 22, 33, 44)
print(88 not in tuple1) # True
Output:
not in operator working on Dictionary
dict1 = {1: "one", 2: "two", 3: "three", 4: "four"}
print("one" not in dict1)
print(3 not in dict1)
print(5 not in dict1)Do comment if you have any doubts or suggestions on this Python operator topic.
Note: IDE: PyCharm 2021.3.3 (Community Edition)
Windows 10
Python 3.10.1
All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.