Use listName[index] syntax to select list elements by index in Python. Just use a list name with square barkiest and pass index value.
list[index_value]Python selects list elements by index examples
A simple example code selects an item from a list by knowing its position in the list.
listA = ['Mon', 'Tue', 'Wed', 'Thu', 'Fri']
res = listA[0]
print("Selected list elements by index:", res)
Output:
Find elements of a list by indices in Python
Use the getitem() method along with the map function to access the list of items.
listA = ['Mon', 'Tue', 'Wed', 'Thu', 'Fri']
listB = [0, 1, 3]
res = list(map(listA.__getitem__, listB))
print(res)
Output: [‘Mon’, ‘Tue’, ‘Thu’]
The operator module provides itemgetter() method which can be used for this purpose.
res=list((itemgetter(*listB)(listA)))
With numpy
res=list(np.array(listA)[listB])
Do comment if you have any doubts or suggestions on this Python list topic.
Note: IDE: PyCharm 2021.3.3 (Community Edition)
Windows 10
Python 3.10.1
All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.