Using any lambda you can check for any element satisfying a condition and returns True in case it finds any True value in Python.
Python any lambda example
Simple example code.
good_foods = ['apple', 'carrot']
junk_foods = ['soda', 'burger']
my_foods = ['banana', 'carrot', 'bread', 'apple', 'soda']
result = (any(map(lambda x: x in junk_foods, my_foods)))
print(result)
Output:
How to achieve python’s any() with a custom predicate?
Answer: Use a generator expression inside of any():
l = list(range(10))
pred = lambda x: x > 10
if any(pred(i) for i in l):
print("foo")
else:
print("bar")
Do comment if you have any doubts or suggestions so this Python any() function topic.
Note: IDE: PyCharm 2021.3.3 (Community Edition)
Windows 10
Python 3.10.1
All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.