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JavaScript find object in array by property value | Example code

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Use the find() method to find objects in the array by property value in JavaScript. As per definition.

The find() method returns the first value in the array if an element in the array satisfies the provided testing function. Otherwise undefined is returned.

myArray.find(x => === '45');

If you want to find its index instead, use findIndex():

myArray.findIndex(x => === '45');

JavaScript finds the object in the array by property value

Simple example code get object by id value from an array of objects.

<!DOCTYPE html>


   var myArray = [{'id':'73','foo':'bar'},

   var res = myArray.find(x => === '45');




JavaScript finds object in array by property value

More example

var myArray = [
 {id:1, name:"bob"},
 {id:2, name:"dan"},
 {id:3, name:"barb"},

// grab the Array item which matchs the id "2"
var item = myArray.find(item => === 2);

// print

Output: dan

Some options.

For loop:

function getByValue(arr, value) {
  for (var i=0, iLen=arr.length; i<iLen; i++) {
    if (arr[i].b == value) return arr[i];


function getByValue3(arr, value) {

  var result = [];
  arr.forEach(function(o){if (o.b == value) result.push(o);} );
  return result? result[0] : null; // or undefined

Filter array of objects, which property matches value, returns an array:

var result = jsObjects.filter(obj => {
  return obj.b === 6

Do comment if you have any doubts or suggestions on this JS object topic.

Note: The All JS Examples codes are tested on the Firefox browser and the Chrome browser.

OS: Windows 10

Code: HTML 5 Version

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