JavaScript string equals ignore case

The simplest way to do string equals ignore case (if you’re not worried about special Unicode characters) is to call toUpperCase or toLowerCase method in JavaScript.

string1.toUpperCase() === string2.toUpperCase();
// or
string1.toLowerCase() === string2.toLowerCase()

JavaScript string equals ignore case

Let’s make both strings lowercase and, that way you will always end up with a case-insensitive search.

<!DOCTYPE html>
<html lang="en">
<body>
  <script>
    var s1 = "aBc";
    var s2 = "AbC";

    if (s1.toLowerCase() === s2.toLowerCase())
    {
      console.log(s1,s2,"String are eqauls")
    }
  </script>
</body>
</html>

Output:

string::localeCompare supports case-insensitive comparisons. you should use localeCompare with the sensitivity: 'accent' option:

function ciEquals(a, b) {
    return typeof a === 'string' && typeof b === 'string'
        ? a.localeCompare(b, undefined, { sensitivity: 'accent' }) === 0
        : a === b;
}

console.log("'a' = 'a'?", ciEquals('a', 'a'));
console.log("'AaA' = 'aAa'?", ciEquals('AaA', 'aAa'));
console.log("'a' = 'á'?", ciEquals('a', 'á'));
console.log("'a' = 'b'?", ciEquals('a', 'b'));

Output:


'a' = 'a'? true
'AaA' = 'aAa'? true
'a' = 'á'? false
'a' = 'b'? false

Another method uses a regular expression.

var string1 = 'someText',
    string2 = 'SometexT',
    regex = new RegExp('^' + string1 + '$', 'i');

if (regex.test(string2)) {
    return true;
}

You can also use string.match().

var string1 = "aBc";
var match = string1.match(/AbC/i);

if(match) {
}

Source: https://stackoverflow.com

Do comment if you have any doubts or suggestions on this Js equal topic.

Note: The All JS Examples codes are tested on the Firefox browser and the Chrome browser.
OS: Windows 10
Code: HTML 5 Version

JavaScript string equals ignore case | Example code