Using enumerate with for-loop and if statement you can get the index of duplicate elements in python list.
Find an index of duplicate elements in list Python Example
Simple example code.
a = [1, 2, 3, 2, 1, 5, 6, 5, 5, 5] res = [idx for idx, item in enumerate(a) if item in a[:idx]] print(res)
Another example using collections
You have to import the collections module for this example.
import collections original = [1, 2, 3, 2, 1, 5, 6, 5, 5, 5] dup = [item for item, count in collections.Counter(original).items() if count > 1] for i in dup: print("index of", i, "=", original.index(i))
index of 1 = 0
index of 2 = 1
index of 5 = 5
How do I get the index of a duplicated string in a list?
Traversing through the length of the list so that we can keep a track of each index and print the index.
import collections original = ['A', 'B', 'A', 'B', 'C'] dup = [item for item, count in collections.Counter(original).items() if count > 1] for i in dup: print("index of", i, "=", original.index(i))
index of A = 0
index of B = 1
Do comment if you have any questions and doubts or suggestions on this Python list topic.
Note: IDE: PyCharm 2021.3.3 (Community Edition)
All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.
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