Use the built-in index() function to find an index of an element in the list in Python. It returns a zero-based index in the list of the first item whose value is equal to x. Raises a ValueError if there is no such item.
list.index(x[, start[, end]])
The optional arguments start and end are interpreted as in the slice notation and are used to limit the search to a particular subsequence of the list.
Python finds an index of the element in a list example
Simple example code.
list1 = ["foo", "bar", "baz"]
res = list1.index("bar")
print("Index of bar:", res)
let’s see an example using the other two start and stop parameters.
vowels = ['a', 'e', 'i', 'o', 'i', 'u']
# Searching for “o” within index 1-5
print(vowels.index("o", 1, 5))
# Searching for “o” within index 1-3
print(vowels.index("o", 0, 2)) # error
Do comment if you have any doubts or suggestions on this Pythono list topic.
Note: IDE: PyCharm 2021.3.3 (Community Edition)
All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.