Python finds the object in the given list that has an attribute (or method result – whatever) equal to the value.
Example Python finds an object in the list
Simple example code.
The naive loop-break on the match. This will assign None to x if you don’t break out of the loop.
import random class Test: def __init__(self, value): self.value = value value = 5 test_list = [Test(random.randint(0, 100)) for x in range(300)] def find(val): for x in test_list: if x.value == val: print("Found it!") break else: x = None return find(value)
Another example single-expression form
This gets the first item from the list that matches the condition, and returns
None if no item matches.
class ProjectFile: def __init__(self, filename: str, number_of_lines: int, language: str, repo: str, size: int): self.filename = filename self.number_of_lines = number_of_lines self.language = language self.repo = repo self.size = size projects = [ ProjectFile( filename="test1.txt", number_of_lines=1, language="English", repo="repo1", size=1, ), ProjectFile( filename="test2.txt", number_of_lines=2, language="German", repo="repo2", size=2 ), ] val = 3 res = next((x for x in projects if x.size == 3), None) print(res)
Do comment if you have any doubts or suggestions on this Python object code.
Note: IDE: PyCharm 2021.3.3 (Community Edition)
All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.
Degree in Computer Science and Engineer: App Developer and has multiple Programming languages experience. Enthusiasm for technology & like learning technical.