Python for loop index starts at 1

Using the slicing method [start:] we can easily skip the first index 0 and start a for-loop at index 1 in Python. It will skip the first element in the loop.

In Python, by default, the index of a for loop starts at 0. However, if you want to start the index at 1, you can use the built-in enumerate() function to add an offset of 1 to the index.

Python for loop index starts at 1 example

A simple example code starting a for loop at the index 1 skips the first index 0. Element b will not print because its index value is 0.

a_list = ["a", "b", "c"]

for item in a_list[1:]:
    print(item)

Output:

Python for loop starts at index with enumerate

If you want to start from 1 instead of 0. This method will not skip the first content just starting indexing at 1.

items = ["a", "b", "c"]

for count, item in enumerate(items, start=1):
    print(count, item)

Output:

1 a
2 b
3 c

Another example

my_list = ['apple', 'banana', 'cherry']

for i, fruit in enumerate(my_list, start=1):
    print(f"{i}. {fruit}")

Comment if you have any doubts or suggestions on this Python for loop topic.

Note: IDE: PyCharm 2021.3.3 (Community Edition)
Windows 10
Python 3.10.1
All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.

Python for loop index starts at 1 | Example code