Python program to print first 10 even numbers using while loop | Code

Use a while loop with if statement condition i % 2 == 0 then only print the first 10 even numbers in Python.

Example print the first 10 even numbers using the while loop in Python

Simple example code prints even numbers of user input values using a while loop in Python. You can use list objects to store value, here we are printing the value using the end keyword.

x = int(input("Enter a number: "))
i = 1

while i <= x:
    if i % 2 == 0:
        print(i, end=" ")
    i = i + 1

Output:

Without if statement

num = 2

while num <= 20:
    print(num)
    num = num + 2

Output:

2
4
6
8
10
12
14
16
18
20

Here’s a simple Python program that uses a while loop to print the first 10 even numbers:

# Initialize a counter and the first even number
counter = 0
even_number = 2

# Use a while loop to print the first 10 even numbers
while counter < 10:
    print(even_number, end=' ')
    
    # Increment the counter and update the even number
    counter += 1
    even_number += 2

# Output:
# 2 4 6 8 10 12 14 16 18 20

In this program, the counter variable keeps track of how many even numbers have been printed, and the even_number variable holds the current even number. The loop continues until the counter reaches 10, printing each even number and updating the counter and even number in each iteration.

Do comment if you have any doubts or suggestions on this Python even number topic.

Note: IDE: PyCharm 2021.3.3 (Community Edition)

Windows 10

Python 3.10.1

All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.