Use a while loop with if statement condition i % 2 == 0 then only print the first 10 even numbers in Python.
Example print first 10 even numbers using while loop in Python
Simple example code print even numbers of user input value using a while loop in Python. You can use list objects to store value, here we are printing the value using the end keyword.
x = int(input("Enter a number: "))
i = 1
while i <= x:
if i % 2 == 0:
print(i, end=" ")
i = i + 1
Output:
Without if statement
num = 2
while num <= 20:
print(num)
num = num + 2
Output:
2
4
6
8
10
12
14
16
18
20
Do comment if you have any doubts or suggestions on this Python even number topic.
Note: IDE: PyCharm 2021.3.3 (Community Edition)
Windows 10
Python 3.10.1
All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.
Explanation of this code
x = int(input(“Enter a number: “))
i = 1
while i <= x:
if i % 2 == 0:
print(i, end=" ")
i = i + 1
in the first line input is taken and the type of input is specified as int.
then in the second line a variable is declared with value 1
the third line declares a while loop with condition as it will run until the value of i will be less than or equal to x
fourth line checks a condition whether the remainder of i/2 is 0 or not, if it is 0 then it will be printed , if not not then it will not be printed
the the thing end=” ” means that each print value will be printed in the same line
the last line means i’s value will increment by 1 after one print is done
I hope this was helpful for you Rohini didi, i said didi as am in std 8th 🙂
THANK YOU!!!
wonderful
C = 0
i = 1
while C != 10:
if i % 2 == 0:
print (i)
C = C+1
i = i +1